1
99:59:59,999 --> 99:59:59,999
1
00:00:00,000 --> 00:00:00,700
.

2
99:59:59,999 --> 99:59:59,999
2
00:00:00,700 --> 00:00:06,250
မ်ဥ္းတစ္ေၾကာင္းက (-3,6) ႏွင့္ (6,0) ဆိုုတဲ့ အမွတ္ေတြကိုုၿဖတ္သြားတယ္.

3
99:59:59,999 --> 99:59:59,999
3
00:00:06,250 --> 00:00:09,390
အဲ့ဒီမ်ဥ္းအတြက္ equation ကိုု point slope form, slope intercept form,

4
00:00:09,390 --> 00:00:11,860
 ႏွင့္ standard form ပံုုစံတိုု႔ျဖင့္ရွာေပးပါ.

4
99:59:59,999 --> 99:59:59,999
5
00:00:11,860 --> 00:00:13,970
ဒါကေတာ့

5
99:59:59,999 --> 99:59:59,999
6
00:00:13,970 --> 00:00:16,030
equation တစ္ေၾကာင္းထဲကိုု 3 မ်ိုဳးေရးတာနဲ႔ တူတူပါပဲ.

6
99:59:59,999 --> 99:59:59,999
7
00:00:16,030 --> 00:00:18,220
ဒီ 3 မ်ိဳးထဲက 1 မ်ိုဳး ကိုုရရင္, က်န္တဲ့ 2 မ်ိဳးကိုု

7
99:59:59,999 --> 99:59:59,999
8
00:00:18,220 --> 00:00:19,230
ျပန္ေၿပာင္းေရးႏိုုင္ပါၿပီ.

8
99:59:59,999 --> 99:59:59,999
9
00:00:19,230 --> 00:00:23,890
ဒါေပမယ့္ အဲဒါေတြက ဘာေတြလဲဆိုုရင္, point slope form ဆိုုတာ

9
99:59:59,999 --> 99:59:59,999
10
00:00:23,890 --> 00:00:28,500
x1 ႏွင့္ y1 က မ်ဥ္းတစ္ေၾကာင္းေပၚက

10
99:59:59,999 --> 99:59:59,999
11
00:00:28,500 --> 00:00:30,160
အမွတ္ေတြဆိုုပါေတာ့

12
00:00:30,160 --> 00:00:32,900
ဒီစာလံုုးေတြေအာက္နားက ခပ္ေသးေသးေရးထားတာကေတာ့

11
99:59:59,999 --> 99:59:59,999
13
00:00:32,900 --> 00:00:34,750
တကယ္လိုု႔ x တစ္လုုံးပဲေရးထားရင္ေတာ့, ကြ်န္ေတာ္တုုိ႔က

12
99:59:59,999 --> 99:59:59,999
14
00:00:34,750 --> 00:00:36,690
ဘယ္တန္ဖိုုးမဆိုုၿဖစ္ႏိုုင္တဲ့ ကိန္းရွင္တစ္ခုုကိုုေၿပာေနတာၿဖစ္ပါတယ္.

13
99:59:59,999 --> 99:59:59,999
15
00:00:36,690 --> 00:00:39,770
တကယ္လိုု႔ x ႏွင့္ y ေအာက္နားေတြမွာ 1 ခပ္ေသးေသးေလးေတြေရးထားတယ္ ဆိုုရင္ေတာ့

14
99:59:59,999 --> 99:59:59,999
16
00:00:39,770 --> 00:00:45,150
ဒါဟာ သီးသန္႔တန္ဖိုုးရွိတဲ့ x သိုု႔မဟုုတ္ y, ဒါမွမဟုုတ္

15
99:59:59,999 --> 99:59:59,999
17
00:00:45,150 --> 00:00:48,450
coordinate တန္ဖိုုးတစ္ခုုကိုုဆိုုလုုိတာ ျဖစ္ပါတယ္.

16
99:59:59,999 --> 99:59:59,999
18
00:00:48,450 --> 00:00:50,030
ကြ်န္ေတာ္တိုု႔ ဥပမာတြက္ရင္ ျမင္ရပါလိမ့္မယ္.

17
99:59:59,999 --> 99:59:59,999
19
00:00:50,030 --> 00:00:52,480
ဒါေပမယ့္ point slope form ဆိုုတာက

18
99:59:59,999 --> 99:59:59,999
20
00:00:52,480 --> 00:00:56,020
အမွတ္တစ္ခုု နဲ႔ မ်ဥ္းေၾကာင္းရဲ႕ slope ကိုုသိတယ္ ဆိုုပါေတာ့

19
99:59:59,999 --> 99:59:59,999
21
00:00:56,020 --> 00:00:58,750
ဒါဆိုု အဲဒီ မ်ဥ္းကိုု point slope form နဲ႔ ေရးရရင္

20
99:59:59,999 --> 99:59:59,999
22
00:00:58,750 --> 00:01:05,209
y-y1 = m*(x-x1)

21
99:59:59,999 --> 99:59:59,999
23
00:01:05,209 --> 00:01:08,830
ဥပမာအားၿဖင့္

22
99:59:59,999 --> 99:59:59,999
24
00:01:08,830 --> 00:01:13,170
(-3,6)ဆိုုတဲ့ အမွတ္က မ်ဥ္းေပၚမွာဆုုိရင္ 

25
00:01:13,170 --> 00:01:19,510
y-6= m(x-(-3)) လိုု႔ေၿပာလိုု႔ရပါတယ္

23
99:59:59,999 --> 99:59:59,999
26
00:01:19,510 --> 00:01:21,120
ဒါဆိုု (x+3) ျဖစ္သြားပါမယ္.

24
99:59:59,999 --> 99:59:59,999
27
00:01:21,120 --> 00:01:23,115
ဒါဟာ သီးသန္႔တန္ဖိုုးရွိတဲ့ x နဲ႔ y ပါ။

25
99:59:59,999 --> 99:59:59,999
28
00:01:23,115 --> 00:01:25,130
ဒီေနရာမွာေတာ့ -3 နဲ႔ 6 ပါ။

26
99:59:59,999 --> 99:59:59,999
29
00:01:25,130 --> 00:01:26,870
ဒါကေတာ့ point slope form ေပါ့။

27
99:59:59,999 --> 99:59:59,999
30
00:01:26,870 --> 00:01:32,790
Slope intercept form ကေတာ့ y=mx+b

28
99:59:59,999 --> 99:59:59,999
31
00:01:32,790 --> 00:01:36,810
ဒီမွာလည္း m က slope, b က 5y-၀င္ရိုုးကိုုၿဖတ္တဲ့အမွတ္

29
99:59:59,999 --> 99:59:59,999
32
00:01:36,810 --> 00:01:40,180
တစ္နည္းအားၿဖင့္ x ကသုုညၿဖစ္တဲ့အခ်ိန္မွာရွိေနတဲ့

30
99:59:59,999 --> 99:59:59,999
33
00:01:40,180 --> 00:01:41,680
y ရဲ႕တန္ဖိုုးပါ။

31
99:59:59,999 --> 99:59:59,999
34
00:01:41,680 --> 00:01:47,680
Standard form ကေတာ့ ax+by=c,

32
99:59:59,999 --> 99:59:59,999
35
00:01:47,680 --> 00:01:50,810
ဒါေတြက အေျခခံအားျဖင့္ ကိန္းဂဏန္း ၂ခုုပါပဲ။

33
99:59:59,999 --> 99:59:59,999
36
00:01:50,810 --> 00:01:52,960
သုူတိုု႔က graph ေပၚမွာ

34
99:59:59,999 --> 99:59:59,999
37
00:01:52,960 --> 00:01:54,430
တိုုက္ရိုုက္ပတ္သတ္မွဳမ်ိုဳးမရွိပါဘူး

38
00:01:54,430 --> 00:01:57,710
ကဲ ဒီ forms ေတြကိုု အေၿဖရွာၾကည့္ၾကပါစိုု႔

35
99:59:59,999 --> 99:59:59,999
39
00:01:57,710 --> 00:01:59,900
ပထမဆံုုး slope ကိုုအရင္ရွာပါမယ္။

36
99:59:59,999 --> 99:59:59,999
40
00:01:59,900 --> 00:02:02,610
Slope ကိုုသိၿပီဆိုုရင္ point slope form က

37
99:59:59,999 --> 99:59:59,999
41
00:02:02,610 --> 00:02:05,820
တြက္ရတာ တကယ္ကိုု အရမ္းလြယ္သြားပါျပီ

38
99:59:59,999 --> 99:59:59,999
42
00:02:05,820 --> 00:02:12,120
slope ျဖစ္တဲ့

39
99:59:59,999 --> 99:59:59,999
43
00:02:12,120 --> 00:02:17,110
m  က y ေျပာင္းလဲမွဳကိုု x ေၿပာင္းလဲမွဳနဲ႔ စားတာပါ။

44
00:02:17,110 --> 00:02:18,480

40
99:59:59,999 --> 99:59:59,999
45
00:02:18,480 --> 00:02:19,940
ဒါဆိုု y ေၿပာင္းလဲမွဳဆိုုတာ ဘာလဲ?

41
99:59:59,999 --> 99:59:59,999
46
00:02:19,940 --> 00:02:23,610
ဒါကိုု ကြ်န္ေတာ္တိုု႔ရဲ႕အဆံုုးမွတ္လိုု႔သေဘာထားရင္

42
99:59:59,999 --> 99:59:59,999
47
00:02:23,610 --> 00:02:26,190
ကြ်န္ေတာ္တိုု႔က ဒီကေနအဲဒီအမွတ္ကိုုသြားတယ္ဆိုုရင္

43
99:59:59,999 --> 99:59:59,999
48
00:02:26,190 --> 00:02:27,460
y ေျပာင္းလဲမွဳကဘာလဲ?

44
99:59:59,999 --> 99:59:59,999
49
00:02:27,460 --> 00:02:30,860
ကြ်န္ေတာ္တိုု႔မွာ 0 ဆိုုတဲ့အဆံုုးမွတ္တစ္ခုုရွိမယ္။ y က 6 ကစၿပီး

45
99:59:59,999 --> 99:59:59,999
50
00:02:30,860 --> 00:02:33,300
0 မွာဆံုုးတယ္။

46
99:59:59,999 --> 99:59:59,999
51
00:02:33,300 --> 00:02:38,650
ဒါဆိုု y ရဲ႕ ဆံုုးမွတ္က 0 ျဖစ္ၿပီး၊ စမွတ္က 6 ျဖစ္တယ္။

47
99:59:59,999 --> 99:59:59,999
52
00:02:38,650 --> 00:02:41,870
ကြ်န္ေတာ္တိုု႔ xရဲ႕ ဆံုုးမွတ္ ဒါမွမဟုုတ္ x-coordinate ကဘာလဲ?

48
99:59:59,999 --> 99:59:59,999
53
00:02:41,870 --> 00:02:44,810
x-coordinate က 6 ပါ။

49
99:59:59,999 --> 99:59:59,999
54
00:02:44,810 --> 00:02:46,690
ကြ်န္ေတာ္ရွင္းေအာင္ၿပန္ေၿပာၿပပါမယ္။

50
99:59:59,999 --> 99:59:59,999
55
00:02:46,690 --> 00:02:53,720
ဒါဆိုု ဒီ 0,

51
99:59:59,999 --> 99:59:59,999
56
00:02:53,720 --> 00:02:59,330
ေနာက္ၿပီး ကြ်န္ေတာ္တိုု႔မွာ y ရဲ႕ စမွတ္ 6 ရွိတယ္။

52
99:59:59,999 --> 99:59:59,999
57
00:02:59,330 --> 00:03:01,580
ေဟာဟိုုက 6 ပါ။

53
99:59:59,999 --> 99:59:59,999
58
00:03:01,580 --> 00:03:06,000
ေနာက္ ကြ်န္ေတာ္တိုု႔က xရဲ႕ ဆံုုးမွတ္ကိုု လိုုခ်င္တယ္။ အဲဒါက ေဟာဒီက 6

54
99:59:59,999 --> 99:59:59,999
59
00:03:06,000 --> 00:03:10,050
ဒါမွမဟုုတ္ ဒီ 6။ ေနာက္ၿပီး ကြ်န္ေတာ္တိုု႔က

55
99:59:59,999 --> 99:59:59,999
60
00:03:10,050 --> 00:03:14,080
အဲဒါကိုု xရဲ႕ စမွတ္ကေန ႏွဳတ္ခ်င္တာပါ။

56
99:59:59,999 --> 99:59:59,999
61
00:03:14,080 --> 00:03:16,800
xရဲ႕ စမွတ္က ေဟာဟိုုမွာပါ

57
99:59:59,999 --> 99:59:59,999
62
00:03:16,800 --> 00:03:19,910
-3 ပဲျဖစ္ပါတယ္။

58
99:59:59,999 --> 99:59:59,999
63
00:03:19,910 --> 00:03:21,880
ေသခ်ာေအာင္ျပန္ေျပာရရင္

59
99:59:59,999 --> 99:59:59,999
64
00:03:21,880 --> 00:03:25,440
ဒီ -3 က ေဟာဟိုုက -3 ပါပဲ။

65
00:03:25,440 --> 00:03:29,500
ကြ်န္ေတာ္ေျပာတာက ဒီအမွတ္ကေနဒီအမွတ္ကိုုသြားရင္

60
99:59:59,999 --> 99:59:59,999
66
00:03:29,500 --> 00:03:31,640
y က 6 မွတ္ေလ်ာ့သြားတယ္

61
99:59:59,999 --> 99:59:59,999
67
00:03:31,640 --> 00:03:32,960
ကြ်န္ေတာ္တိုု႔ 6 ကေန 0 ကိုုေရာက္သြားတယ္။

62
99:59:59,999 --> 99:59:59,999
68
00:03:32,960 --> 00:03:37,650
ကြ်န္ေတာ္တိုု႔ရဲ႕ y က 6 မွတ္ေလ်ာ့သြားပါတယ္။

63
99:59:59,999 --> 99:59:59,999
69
00:03:37,650 --> 00:03:40,420
ဒါေၾကာင့္ 0-6 ဆိုုေတာ့ -6 ရပါတယ္။

64
99:59:59,999 --> 99:59:59,999
70
00:03:40,420 --> 00:03:41,070
.

71
00:03:41,070 --> 00:03:43,150
y က 6 မွတ္ေလ်ာ့သြားတယ္

72
00:03:43,150 --> 00:03:45,180
ကြ်န္ေတာ္တိုု႔ ဒီအမွတ္ကေန ဒီအမွတ္ကိုုသြားရင္

73
00:03:45,180 --> 00:03:46,060
x ကဘာၿဖစ္မလဲ?

65
99:59:59,999 --> 99:59:59,999
74
00:03:46,060 --> 00:03:49,560
-3 ကေန 6 ကိုုသြားတယ္ဆိုုေတာ့ x က 9 မွတ္တိုုးလာသင့္တာေပါ့

66
99:59:59,999 --> 99:59:59,999
75
00:03:49,560 --> 00:03:54,870
အဲဒါကိုုတြက္မယ္ဆိုုရင္ -3 ကိုုယူၿပီး 6 ထဲကႏွုဳတ္ရင္

76
00:03:54,870 --> 00:03:58,550
6 ကိုု 3 ေပါင္းတာနဲ႔ တုူတူပဲေပါ့ 9 ရပါတယ္

67
99:59:59,999 --> 99:59:59,999
77
00:03:58,550 --> 00:04:00,120
ေနာက္ၿပီး -6 ကိုု 9 နဲ႔စားရင္ ဘယ္ေလာက္ရလဲ

68
99:59:59,999 --> 99:59:59,999
78
00:04:00,120 --> 00:04:04,060
အဲဒါကိုုရွင္းလိုုက္ရင္ -2/3 က်န္ပါတယ္

69
99:59:59,999 --> 99:59:59,999
79
00:04:04,060 --> 00:04:06,950
ပိုုင္းေဝေရာ ပိုုင္းေၿခကိုုပါ 3 နဲ႔စားလိုုက္တာပါ

70
99:59:59,999 --> 99:59:59,999
80
00:04:06,950 --> 00:04:09,860
ဒါဆိုု ဒါဟာကြ်န္ေတာ္တိုု႔ရဲ႕ slope ျဖစ္တဲ့ -2/3 ပါ

71
99:59:59,999 --> 99:59:59,999
81
00:04:09,860 --> 00:04:12,800
အခုုဆိုု ကြ်န္ေတာ္တိုု႔က point slope form ကိုုအသံုုးၿပဳလိုု႔ရပါၿပီ

82
00:04:12,800 --> 00:04:15,760
ကြ်န္ေတာ္တိုု႔မွာ အမွတ္တစ္မွတ္ရွိပါတယ္။ ဘယ္အမွတ္မဆိုု သံုုးလိုု႔ရပါတယ္။

72
99:59:59,999 --> 99:59:59,999
83
00:04:15,760 --> 00:04:18,149
ကြ်န္ေတာ္ကေတာ့ (-3,6) ကိုုပဲသံုုးလိုုက္ပါမယ္

73
99:59:59,999 --> 99:59:59,999
84
00:04:18,149 --> 00:04:19,269
ကြ်န္ေတာ္တိုု႔မွာ slope လည္းရွိပါတယ္

74
99:59:59,999 --> 99:59:59,999
85
00:04:19,269 --> 00:04:20,910
point slope form နဲ႔ေရးၾကည့္ရေအာင္

75
99:59:59,999 --> 99:59:59,999
86
00:04:20,910 --> 00:04:29,050
.

76
99:59:59,999 --> 99:59:59,999
87
00:04:29,050 --> 00:04:32,910
y ထဲကႏွဳတ္ဖိုု႔ ကြ်န္ေတာ္တိုု႔

77
99:59:59,999 --> 99:59:59,999
88
00:04:32,910 --> 00:04:35,030
ဒီအမွတ္၂ခုုထဲက ၾကိဳက္တဲ့တစ္ခုုယုူလိုု႔ရပါတယ္. ကြ်န္ေတာ္ကဒီတစ္ခုုယူပါမယ္။

78
99:59:59,999 --> 99:59:59,999
89
00:04:35,030 --> 00:04:42,990
y minus ေဟာဒီက y ရဲ႕ တန္ဖိုုး, ဒါဆိုု y-6=

79
99:59:59,999 --> 99:59:59,999
90
00:04:42,990 --> 00:04:51,480
slope တန္ဖိုုးျဖစ္တဲ့ (-2/3) အေၿမွာက္ x minus 

91
00:04:51,480 --> 00:04:51,930
x-coordinate.

92
00:04:51,930 --> 00:04:55,490
x-coordinate က -3

93
00:04:55,490 --> 00:05:00,370
ဆိုုေတာ့ x minus (-3) ဆိုုရင္ရပါၿပီ။

80
99:59:59,999 --> 99:59:59,999
94
00:05:00,370 --> 00:05:01,570
ဒါကိုုနဲနဲထပ္ရွင္းလိုု႔ရပါေသးတယ္

81
99:59:59,999 --> 99:59:59,999
95
00:05:01,570 --> 00:05:08,650
y-6 = -2/3 အေၿမွာက္ x.

82
99:59:59,999 --> 99:59:59,999
96
00:05:08,650 --> 00:05:12,610
x minus -3 က x +3 နဲ႔တူတူပါပဲ

83
99:59:59,999 --> 99:59:59,999
97
00:05:12,610 --> 00:05:15,760
ဒါကေတာ့ ကြ်န္ေတာ္တိုု႔ရဲ႕ point slope form ပါ။

84
99:59:59,999 --> 99:59:59,999
98
00:05:15,760 --> 00:05:19,270
အခုု ကြ်န္ေတာ္တိုု႔က ဒီဟာ ကိုုပဲ 

99
00:05:19,270 --> 00:05:23,500
slope intercept form ကိုု ေျပာင္းလဲလိုုက္လိုု႔ရပါတယ္

85
99:59:59,999 --> 99:59:59,999
100
00:05:23,500 --> 00:05:24,130
ကဲ လုုပ္ၾကည့္ရေအာင္

86
99:59:59,999 --> 99:59:59,999
101
00:05:24,130 --> 00:05:27,560
slope intercept ကိုု လိေမာ္ေရာင္နဲ႔ လုုပ္ၾကမယ္ေနာ္

87
99:59:59,999 --> 99:59:59,999
102
00:05:27,560 --> 00:05:30,960
ကြ်န္ေတာ္တိုု႔မွာ slope intercept ရွိပါတယ္

88
99:59:59,999 --> 99:59:59,999
103
00:05:30,960 --> 00:05:35,200
.

89
99:59:59,999 --> 99:59:59,999
104
00:05:35,200 --> 00:05:37,040
ဒီဟာကိုုဘယ္လိုုရွင္းၾကမလဲဆိုုေတာ့

90
99:59:59,999 --> 99:59:59,999
105
00:05:37,040 --> 00:05:41,510
ကြ်န္ေတာ္တိုု႔က -2/3 ကိုုေၿမွာက္လိုုက္လိုု႔ရပါတယ္။

91
99:59:59,999 --> 99:59:59,999
106
00:05:41,510 --> 00:05:44,150
ကြ်န္ေတာ္က -2/3 ကိုု အထဲဝင္ေျမွာက္မွာပါ။ y-6=

92
99:59:59,999 --> 99:59:59,999
107
00:05:44,150 --> 00:05:48,950
-2/3 အေျမွာက္ x က -2/3x ပါ

93
99:59:59,999 --> 99:59:59,999
108
00:05:48,950 --> 00:05:53,890
-2/3 အေျမွာက္ 3 က -2 ရပါတယ္

94
99:59:59,999 --> 99:59:59,999
109
00:05:53,890 --> 00:05:56,150
အခုု slope intercept form အေနနဲ႔ရဖိုု႔

95
99:59:59,999 --> 99:59:59,999
110
00:05:56,150 --> 00:05:59,270
6 ကိုု ၂ဖက္စလုုံးမွာ ေပါင္းလုုိက္မယ္ဆိုု ဘယ္ဖက္အျခမ္းက 6 ကိုု

96
99:59:59,999 --> 99:59:59,999
111
00:05:59,270 --> 00:06:02,380
ဖယ္ျပီးသားျဖစ္သြားမွာပါ. equation ရဲ႕ ၂ဖက္စလုုံးကိုု

97
99:59:59,999 --> 99:59:59,999
112
00:06:02,380 --> 00:06:04,400
6 ေပါင္းရေအာင္

98
99:59:59,999 --> 99:59:59,999
113
00:06:04,400 --> 00:06:06,010
ဘယ္ဘက္အျခမ္းမွာ y တစ္ခုုထဲက်န္ၿပီး

99
99:59:59,999 --> 99:59:59,999
114
00:06:06,010 --> 00:06:08,090
ဒီေကာင္ေတြကေတာ့ ေၾကသြားမွာပါ

100
99:59:59,999 --> 99:59:59,999
115
00:06:08,090 --> 00:06:12,830
အခုုဆိုု y= -2/3x

101
99:59:59,999 --> 99:59:59,999
116
00:06:12,830 --> 00:06:15,810
-2 အေပါင္း 6 က +4 ရပါတယ္

102
99:59:59,999 --> 99:59:59,999
117
00:06:15,810 --> 00:06:19,890
ဒါကကြ်န္ေတာ္တိုု႔ရဲ႕ slope intercept form ပါ

103
99:59:59,999 --> 99:59:59,999
118
00:06:19,890 --> 00:06:22,590
mx အေပါင္း b, ဒါက ကြ်န္ေတာ္တိုု႔ y ျဖတ္မွတ္ပါ။

104
99:59:59,999 --> 99:59:59,999
119
00:06:22,590 --> 00:06:24,480
အခုု ကြ်န္ေတာ္တိုု႔ standard form

105
99:59:59,999 --> 99:59:59,999
120
00:06:24,480 --> 00:06:25,730
ရွာဖိုု႔ပဲက်န္ပါေတာ့တယ္

106
99:59:59,999 --> 99:59:59,999
121
00:06:25,730 --> 00:06:30,440
.

107
99:59:59,999 --> 99:59:59,999
122
00:06:30,440 --> 00:06:32,840
ဒီတစ္ခါလည္း ရွိၿပီးသား equationကိုု ေျပာင္းလုုိက္ရံုုပါပဲ

108
99:59:59,999 --> 99:59:59,999
123
00:06:32,840 --> 00:06:34,500
x ေရာ y ေရာ equation ရဲ႕

109
99:59:59,999 --> 99:59:59,999
124
00:06:34,500 --> 00:06:36,130
ဘယ္ဘက္အျခမ္းကိုု ေျပာင္းေပးရမွာပါ

110
99:59:59,999 --> 99:59:59,999
125
00:06:36,130 --> 00:06:40,140
ဒါဆိုု equation ရဲ႕ ၂ဖက္စလံုုးကိုု 2/3 နဲ႔ေပါင္းၾကရေအာင္

111
99:59:59,999 --> 99:59:59,999
126
00:06:40,140 --> 00:06:42,140
ကြ်န္ေတာ္ ဒီက စပါမယ္

112
99:59:59,999 --> 99:59:59,999
127
00:06:42,140 --> 00:06:45,950
ကြ်န္ေတာ္တိုု႔မွာ y = -2/3x +4 ရွိပါတယ္

113
99:59:59,999 --> 99:59:59,999
128
00:06:45,950 --> 00:06:47,540
ဒါက slope intercept form ပါ

114
99:59:59,999 --> 99:59:59,999
129
00:06:47,540 --> 00:06:53,790
2/3x ကိုု equation ရဲ႕ ၂ဖက္စလုုံးကိုု

115
99:59:59,999 --> 99:59:59,999
130
00:06:53,790 --> 00:06:55,040
ေပါင္းၾကရေအာင္

116
99:59:59,999 --> 99:59:59,999
131
00:06:55,040 --> 00:06:57,650
.

117
99:59:59,999 --> 99:59:59,999
132
00:06:57,650 --> 00:07:00,060
ကြ်န္ေတာ္ဒီလိုုလုုပ္တာဟာ equation ရဲ႕

118
99:59:59,999 --> 99:59:59,999
133
00:07:00,060 --> 00:07:02,350
ညာဖက္မွာ ဒီ -2/3x ကိုု မရွိေအာင္လိုု႔ပါ

119
99:59:59,999 --> 99:59:59,999
134
00:07:02,350 --> 00:07:05,010
equation ရဲ႕ ဘယ္ဖက္အၿခမ္းက

120
99:59:59,999 --> 99:59:59,999
135
00:07:05,010 --> 00:07:07,730

121
99:59:59,999 --> 99:59:59,999
136
00:07:07,730 --> 00:07:09,890
အခုုဘာၿဖစ္သြားျပီလဲ?

122
99:59:59,999 --> 99:59:59,999
137
00:07:09,890 --> 00:07:16,390
2/3x အေပါင္း y, ဒါက ကြ်န္ေတာ့္ equation ရဲ႕

123
99:59:59,999 --> 99:59:59,999
138
00:07:16,390 --> 00:07:20,220
ဘယ္ဖက္အျခမ္းပါ။ ဒီေကာင္ေတြက ေၾကသြားတယ္ဆိုုေတာ့

124
99:59:59,999 --> 99:59:59,999
139
00:07:20,220 --> 00:07:22,650
4 ရပါတယ္

125
99:59:59,999 --> 99:59:59,999
140
00:07:22,650 --> 00:07:25,580
ဒါဆိုု ဒီ standard form ကိုုရပါၿပီ

126
99:59:59,999 --> 99:59:59,999
141
00:07:25,580 --> 00:07:26,790
.

127
99:59:59,999 --> 99:59:59,999
142
00:07:26,790 --> 00:07:30,030
အပိုုင္းကိန္းေဖ်ာက္ခ်င္တယ္ဆိုုရင္ေတာ့

128
99:59:59,999 --> 99:59:59,999
143
00:07:30,030 --> 00:07:32,340
၂ဖက္စလုုံးကိုု 3 နဲ႔ေျမွာက္လိုု႔ရပါတယ္

144
00:07:32,340 --> 00:07:33,860
.

145
00:07:33,860 --> 00:07:36,400
အဲ့လိုုလုုပ္ရင္ ဘာရမလဲ?

129
99:59:59,999 --> 99:59:59,999
146
00:07:36,400 --> 00:07:40,220
2/3xကိုု 3နဲ႔ေျမွာက္ရင္ 2xရပါတယ္

130
99:59:59,999 --> 99:59:59,999
147
00:07:40,220 --> 00:07:43,440
yကိုု 3နဲ႔ေျမွာက္ရင္ 3y ရပါတယ္

131
99:59:59,999 --> 99:59:59,999
148
00:07:43,440 --> 00:07:45,700
4 အေျမွာက္ 3 က 12

132
99:59:59,999 --> 99:59:59,999
149
00:07:45,700 --> 00:07:47,620
equation ၂ခုုကတူတူပါပဲ။ ၂ဖက္စလုုံးကိုု 3နဲ႔ေျမွာက္လိုုက္တာပါပဲ

133
99:59:59,999 --> 99:59:59,999
150
00:07:47,620 --> 00:07:48,760

151
00:07:48,760 --> 00:07:50,190
ဘယ္ဖက္အျခမ္းကိုုေျမွာက္ရင္ ညာဖက္ကိုုလည္းေျမွာက္ရမယ္

134
99:59:59,999 --> 99:59:59,999
152
00:07:50,190 --> 00:07:52,680
.

153
00:07:52,680 --> 00:07:56,160
ဒါဆိုု standard form ရပါၿပီ