WEBVTT 00:00:00.000 --> 00:00:00.550 00:00:00.550 --> 00:00:03.240 I think it's pretty common knowledge how to find the area 00:00:03.240 --> 00:00:06.030 of the triangle if we know the length of its base 00:00:06.030 --> 00:00:07.250 and its height. 00:00:07.250 --> 00:00:10.540 So, for example, if that's my triangle, and this length right 00:00:10.540 --> 00:00:14.910 here-- this base-- is of length b and the height right here is 00:00:14.910 --> 00:00:19.080 of length h, it's pretty common knowledge that the area of this 00:00:19.080 --> 00:00:23.170 triangle is going to be equal to 1/2 times the base 00:00:23.170 --> 00:00:24.440 times the height. 00:00:24.440 --> 00:00:30.240 So, for example, if the base was equal to 5 and the height 00:00:30.240 --> 00:00:37.180 was equal to 6, then our area would be 1/2 times 5 times 6, 00:00:37.180 --> 00:00:41.770 which is 1/2 times 30-- which is equal to 15. 00:00:41.770 --> 00:00:45.120 Now what is less well-known is how to figure out the area of a 00:00:45.120 --> 00:00:48.250 triangle when you're only given the sides of the triangle. 00:00:48.250 --> 00:00:49.740 When you aren't given the height. 00:00:49.740 --> 00:00:53.470 So, for example, how do you figure out a triangle 00:00:53.470 --> 00:00:55.570 where I just give you the lengths of the sides. 00:00:55.570 --> 00:01:00.530 Let's say that's side a, side b, and side c. a, b, and c are 00:01:00.530 --> 00:01:01.640 the lengths of these sides. 00:01:01.640 --> 00:01:03.360 How do you figure that out? 00:01:03.360 --> 00:01:05.270 And to do that we're going to apply something 00:01:05.270 --> 00:01:06.430 called Heron's Formula. 00:01:06.430 --> 00:01:12.210 00:01:12.210 --> 00:01:13.790 And I'm not going to prove it in this video. 00:01:13.790 --> 00:01:15.200 I'm going to prove it in a future video. 00:01:15.200 --> 00:01:17.400 And really to prove it you already probably have 00:01:17.400 --> 00:01:18.720 the tools necessary. 00:01:18.720 --> 00:01:20.480 It's really just the Pythagorean theorem and 00:01:20.480 --> 00:01:22.220 a lot of hairy algebra. 00:01:22.220 --> 00:01:24.230 But I'm just going to show you the formula now and how to 00:01:24.230 --> 00:01:26.760 apply it, and then you'll hopefully appreciate that it's 00:01:26.760 --> 00:01:28.590 pretty simple and pretty easy to remember. 00:01:28.590 --> 00:01:31.660 And it can be a nice trick to impress people with. 00:01:31.660 --> 00:01:36.320 So Heron's Formula says first figure out this third variable 00:01:36.320 --> 00:01:38.640 S, which is essentially the perimeter of this 00:01:38.640 --> 00:01:40.660 triangle divided by 2. 00:01:40.660 --> 00:01:45.810 a plus b plus c, divided by 2. 00:01:45.810 --> 00:01:49.480 Then once you figure out S, the area of your triangle-- of this 00:01:49.480 --> 00:01:55.840 triangle right there-- is going to be equal to the square root 00:01:55.840 --> 00:01:59.710 of S-- this variable S right here that you just calculated-- 00:01:59.710 --> 00:02:10.540 times S minus a, times S minus b, times S minus c. 00:02:10.540 --> 00:02:12.480 That's Heron's Formula right there. 00:02:12.480 --> 00:02:13.830 This combination. 00:02:13.830 --> 00:02:16.130 Let me square it off for you. 00:02:16.130 --> 00:02:18.700 So that right there is Heron's Formula. 00:02:18.700 --> 00:02:21.610 And if that looks a little bit daunting-- it is a little bit 00:02:21.610 --> 00:02:24.290 more daunting, clearly, than just 1/2 times base 00:02:24.290 --> 00:02:25.290 times height. 00:02:25.290 --> 00:02:28.040 Let's do it with an actual example or two, and actually 00:02:28.040 --> 00:02:31.350 see this is actually not so bad. 00:02:31.350 --> 00:02:33.320 So let's say I have a triangle. 00:02:33.320 --> 00:02:35.300 I'll leave the formula up there. 00:02:35.300 --> 00:02:37.460 So let's say I have a triangle that has sides 00:02:37.460 --> 00:02:44.920 of length 9, 11, and 16. 00:02:44.920 --> 00:02:47.040 So let's apply Heron's Formula. 00:02:47.040 --> 00:02:51.190 S in this situation is going to be the perimeter divided by 2. 00:02:51.190 --> 00:02:56.630 So 9 plus 11 plus 16, divided by 2. 00:02:56.630 --> 00:03:00.430 Which is equal to 9 plus 11-- is 20-- plus 16 is 00:03:00.430 --> 00:03:04.660 36, divided by 2 is 18. 00:03:04.660 --> 00:03:09.430 And then the area by Heron's Formula is going to be equal to 00:03:09.430 --> 00:03:19.380 the square root of S-- 18-- times S minus a-- S minus 9. 00:03:19.380 --> 00:03:27.790 18 minus 9, times 18 minus 11, times 18 minus 16. 00:03:27.790 --> 00:03:31.490 00:03:31.490 --> 00:03:38.200 And then this is equal to the square root of 18 00:03:38.200 --> 00:03:44.730 times 9 times 7 times 2. 00:03:44.730 --> 00:03:47.340 Which is equal to-- let's see, 2 times 18 is 36. 00:03:47.340 --> 00:03:48.900 So I'll just rearrange it a bit. 00:03:48.900 --> 00:03:56.700 This is equal to the square root of 36 times 9 times 7, 00:03:56.700 --> 00:04:05.540 which is equal to the square root of 36 times the square 00:04:05.540 --> 00:04:09.330 root of 9 times the square root of 7. 00:04:09.330 --> 00:04:14.130 The square root of 36 is just 6. 00:04:14.130 --> 00:04:16.040 This is just 3. 00:04:16.040 --> 00:04:17.750 And we don't deal with the negative square roots, 00:04:17.750 --> 00:04:19.920 because you can't have negative side lengths. 00:04:19.920 --> 00:04:23.460 And so this is going to be equal to 18 times 00:04:23.460 --> 00:04:26.120 the square root of 7. 00:04:26.120 --> 00:04:28.060 So just like that, you saw it, it only took a couple of 00:04:28.060 --> 00:04:30.760 minutes to apply Heron's Formula, or even less than 00:04:30.760 --> 00:04:33.420 that, to figure out that the area of this triangle 00:04:33.420 --> 00:04:38.710 right here is equal to 18 square root of seven. 00:04:38.710 --> 00:04:42.040 Anyway, hopefully you found that pretty neat. 00:04:42.040 --> 00:04:42.331